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30172493433 = 310057497811
BaseRepresentation
bin11100000110011010…
…111011011001111001
32212212202212110212210
4130012122323121321
5443243124242213
621505553125333
72115462651105
oct340632733171
985782773783
1030172493433
1111883649995
125a20859849
132acb03b314
14166330a905
15bb8d4d0c3
hex7066bb679

30172493433 has 4 divisors (see below), whose sum is σ = 40229991248. Its totient is φ = 20114995620.

The previous prime is 30172493431. The next prime is 30172493453. The reversal of 30172493433 is 33439427103.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 30172493433 - 21 = 30172493431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30172493391 and 30172493400.

It is not an unprimeable number, because it can be changed into a prime (30172493431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5028748903 + ... + 5028748908.

It is an arithmetic number, because the mean of its divisors is an integer number (10057497812).

Almost surely, 230172493433 is an apocalyptic number.

It is an amenable number.

30172493433 is a deficient number, since it is larger than the sum of its proper divisors (10057497815).

30172493433 is a wasteful number, since it uses less digits than its factorization.

30172493433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10057497814.

The product of its (nonzero) digits is 163296, while the sum is 39.

The spelling of 30172493433 in words is "thirty billion, one hundred seventy-two million, four hundred ninety-three thousand, four hundred thirty-three".

Divisors: 1 3 10057497811 30172493433