Base | Representation |
---|---|
bin | 101011111100111000101… |
… | …100001100110101111010 |
3 | 101200201221210222200202102 |
4 | 223330320230030311322 |
5 | 343441100124320442 |
6 | 10231302424103402 |
7 | 431132113633454 |
oct | 53747054146572 |
9 | 11621853880672 |
10 | 3020313120122 |
11 | a649a9020561 |
12 | 409434904b62 |
13 | 18ba7804a3cc |
14 | a6280a092d4 |
15 | 53872c11232 |
hex | 2bf38b0cd7a |
3020313120122 has 8 divisors (see below), whose sum is σ = 4530646804500. Its totient is φ = 1510097518624.
The previous prime is 3020313120119. The next prime is 3020313120133. The reversal of 3020313120122 is 2210213130203.
It can be written as a sum of positive squares in 2 ways, for example, as 2098676639761 + 921636480361 = 1448681^2 + 960019^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-4 number, since 4×30203131201224 (a number of 51 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3020313120094 and 3020313120103.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29456747 + ... + 29559102.
Almost surely, 23020313120122 is an apocalyptic number.
3020313120122 is a deficient number, since it is larger than the sum of its proper divisors (1510333684378).
3020313120122 is a wasteful number, since it uses less digits than its factorization.
3020313120122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59041440.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 3020313120122 its reverse (2210213130203), we get a palindrome (5230526250325).
The spelling of 3020313120122 in words is "three trillion, twenty billion, three hundred thirteen million, one hundred twenty thousand, one hundred twenty-two".
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