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30231101211002 = 215115550605501
BaseRepresentation
bin1101101111110101110100…
…00011001000000101111010
310222001001202102101122212022
412313322322003020011322
512430301243402223002
6144143550504114442
76240060604310606
oct667727203100572
9128031672348768
1030231101211002
1196a5a3556841a
123482ba6765a22
1313b3a1c009453
1476729bc4c506
153765a889bba2
hex1b7eba0c817a

30231101211002 has 4 divisors (see below), whose sum is σ = 45346651816506. Its totient is φ = 15115550605500.

The previous prime is 30231101210957. The next prime is 30231101211023. The reversal of 30231101211002 is 20011210113203.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 23316836220001 + 6914264991001 = 4828751^2 + 2629499^2 .

It is a super-3 number, since 3×302311012110023 (a number of 41 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557775302749 + ... + 7557775302752.

Almost surely, 230231101211002 is an apocalyptic number.

30231101211002 is a deficient number, since it is larger than the sum of its proper divisors (15115550605504).

30231101211002 is a wasteful number, since it uses less digits than its factorization.

30231101211002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15115550605503.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 30231101211002 its reverse (20011210113203), we get a palindrome (50242311324205).

The spelling of 30231101211002 in words is "thirty trillion, two hundred thirty-one billion, one hundred one million, two hundred eleven thousand, two".

Divisors: 1 2 15115550605501 30231101211002