Base | Representation |
---|---|
bin | 1101110000001100100100… |
… | …00000001000101110011011 |
3 | 10222002020021120100211121212 |
4 | 12320012102000020232123 |
5 | 12431001301421143121 |
6 | 144153330423453335 |
7 | 6241002343326416 |
oct | 670062200105633 |
9 | 128066246324555 |
10 | 30243314240411 |
11 | 97001324a1158 |
12 | 34854348b724b |
13 | 13b4c1733a97c |
14 | 767ad9c80b7d |
15 | 376a70b9c25b |
hex | 1b8192008b9b |
30243314240411 has 4 divisors (see below), whose sum is σ = 30346533743232. Its totient is φ = 30140094737592.
The previous prime is 30243314240351. The next prime is 30243314240413. The reversal of 30243314240411 is 11404241334203.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30243314240411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30243314240413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51609750971 + ... + 51609751556.
It is an arithmetic number, because the mean of its divisors is an integer number (7586633435808).
Almost surely, 230243314240411 is an apocalyptic number.
30243314240411 is a deficient number, since it is larger than the sum of its proper divisors (103219502821).
30243314240411 is a wasteful number, since it uses less digits than its factorization.
30243314240411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103219502820.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 30243314240411 its reverse (11404241334203), we get a palindrome (41647555574614).
The spelling of 30243314240411 in words is "thirty trillion, two hundred forty-three billion, three hundred fourteen million, two hundred forty thousand, four hundred eleven".
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