Base | Representation |
---|---|
bin | 1101110010001010110110… |
… | …01001000001110111001111 |
3 | 10222022201021121020222211211 |
4 | 12321011123021001313033 |
5 | 12433104130001121310 |
6 | 144244422212555251 |
7 | 6245622433666420 |
oct | 671053311016717 |
9 | 128281247228754 |
10 | 30311113301455 |
11 | 9726964282208 |
12 | 34965b6622b27 |
13 | 13bb4307b547c |
14 | 76b0cc453647 |
15 | 3786dce57c8a |
hex | 1b915b241dcf |
30311113301455 has 16 divisors (see below), whose sum is σ = 41665530360384. Its totient is φ = 20736761633280.
The previous prime is 30311113301453. The next prime is 30311113301459. The reversal of 30311113301455 is 55410331111303.
It is not a de Polignac number, because 30311113301455 - 21 = 30311113301453 is a prime.
It is a super-3 number, since 3×303111133014553 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30311113301453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1000021576 + ... + 1000051885.
It is an arithmetic number, because the mean of its divisors is an integer number (2604095647524).
Almost surely, 230311113301455 is an apocalyptic number.
30311113301455 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
30311113301455 is a deficient number, since it is larger than the sum of its proper divisors (11354417058929).
30311113301455 is a wasteful number, since it uses less digits than its factorization.
30311113301455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2000073906.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 30311113301455 its reverse (55410331111303), we get a palindrome (85721444412758).
The spelling of 30311113301455 in words is "thirty trillion, three hundred eleven billion, one hundred thirteen million, three hundred one thousand, four hundred fifty-five".
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