Base | Representation |
---|---|
bin | 100010011101100100100001… |
… | …0000111001111110100001011 |
3 | 1110202022001220021001110211221 |
4 | 1010323021002013033310023 |
5 | 304213000411104410011 |
6 | 2552412333554302511 |
7 | 120564341321101216 |
oct | 10473110207176413 |
9 | 1422261807043757 |
10 | 303131311013131 |
11 | 886502a34a4957 |
12 | 29bb8a66887a37 |
13 | 1001b2105cc253 |
14 | 54bd8c2d8477d |
15 | 250a21b07e971 |
hex | 113b2421cfd0b |
303131311013131 has 4 divisors (see below), whose sum is σ = 313584114841200. Its totient is φ = 292678507185064.
The previous prime is 303131311013039. The next prime is 303131311013137. The reversal of 303131311013131 is 131310113131303.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 303131311013131 - 213 = 303131311004939 is a prime.
It is a super-2 number, since 2×3031313110131312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 303131311013096 and 303131311013105.
It is not an unprimeable number, because it can be changed into a prime (303131311013137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5226401913991 + ... + 5226401914048.
It is an arithmetic number, because the mean of its divisors is an integer number (78396028710300).
Almost surely, 2303131311013131 is an apocalyptic number.
303131311013131 is a deficient number, since it is larger than the sum of its proper divisors (10452803828069).
303131311013131 is a wasteful number, since it uses less digits than its factorization.
303131311013131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10452803828068.
The product of its (nonzero) digits is 729, while the sum is 25.
Adding to 303131311013131 its reverse (131310113131303), we get a palindrome (434441424144434).
The spelling of 303131311013131 in words is "three hundred three trillion, one hundred thirty-one billion, three hundred eleven million, thirteen thousand, one hundred thirty-one".
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