Base | Representation |
---|---|
bin | 101100001000111110111… |
… | …001010001101101011001 |
3 | 101201222111001001220102220 |
4 | 230020332321101231121 |
5 | 344144200320104423 |
6 | 10241251343214253 |
7 | 432102024355626 |
oct | 54107671215531 |
9 | 11658431056386 |
10 | 3033302113113 |
11 | a6a463a68208 |
12 | 40ba5a8a7389 |
13 | 19006806708c |
14 | a6b53b0b34d |
15 | 53d831db9e3 |
hex | 2c23ee51b59 |
3033302113113 has 8 divisors (see below), whose sum is σ = 4044425219808. Its totient is φ = 2022190207584.
The previous prime is 3033302113111. The next prime is 3033302113159. The reversal of 3033302113113 is 3113112033303.
3033302113113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3033302113113 - 21 = 3033302113111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3033302113111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2146620 + ... + 3267197.
It is an arithmetic number, because the mean of its divisors is an integer number (505553152476).
Almost surely, 23033302113113 is an apocalyptic number.
It is an amenable number.
3033302113113 is a deficient number, since it is larger than the sum of its proper divisors (1011123106695).
3033302113113 is a wasteful number, since it uses less digits than its factorization.
3033302113113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5600583.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 3033302113113 its reverse (3113112033303), we get a palindrome (6146414146416).
The spelling of 3033302113113 in words is "three trillion, thirty-three billion, three hundred two million, one hundred thirteen thousand, one hundred thirteen".
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