Base | Representation |
---|---|
bin | 101100001111011101001… |
… | …110000000001000000111 |
3 | 101202122102110222110210200 |
4 | 230033131032000020013 |
5 | 344302414322013133 |
6 | 10244401215421543 |
7 | 432436211530245 |
oct | 54173516001007 |
9 | 11678373873720 |
10 | 3040253313543 |
11 | a72400810a56 |
12 | 41127a8248b3 |
13 | 190905215124 |
14 | a7212da3795 |
15 | 5413d5b6913 |
hex | 2c3dd380207 |
3040253313543 has 12 divisors (see below), whose sum is σ = 4391628696000. Its totient is φ = 2026765532736.
The previous prime is 3040253313527. The next prime is 3040253313577. The reversal of 3040253313543 is 3453133520403.
3040253313543 is a `hidden beast` number, since 3 + 0 + 40 + 253 + 313 + 54 + 3 = 666.
It is not a de Polignac number, because 3040253313543 - 24 = 3040253313527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3040253313498 and 3040253313507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3040253312543) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5558418 + ... + 6080831.
It is an arithmetic number, because the mean of its divisors is an integer number (365969058000).
Almost surely, 23040253313543 is an apocalyptic number.
3040253313543 is a deficient number, since it is larger than the sum of its proper divisors (1351375382457).
3040253313543 is a wasteful number, since it uses less digits than its factorization.
3040253313543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11668278 (or 11668275 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 36.
Adding to 3040253313543 its reverse (3453133520403), we get a palindrome (6493386833946).
The spelling of 3040253313543 in words is "three trillion, forty billion, two hundred fifty-three million, three hundred thirteen thousand, five hundred forty-three".
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