Base | Representation |
---|---|
bin | 101100001111011101100… |
… | …100001000001011001001 |
3 | 101202122102212220011002022 |
4 | 230033131210020023021 |
5 | 344302422313114143 |
6 | 10244401544014225 |
7 | 432436312035245 |
oct | 54173544101311 |
9 | 11678385804068 |
10 | 3040259113673 |
11 | a72404012751 |
12 | 411280761375 |
13 | 190906496162 |
14 | a7213a73425 |
15 | 5413dd60268 |
hex | 2c3dd9082c9 |
3040259113673 has 4 divisors (see below), whose sum is σ = 3040271924688. Its totient is φ = 3040246302660.
The previous prime is 3040259113667. The next prime is 3040259113763. The reversal of 3040259113673 is 3763119520403.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3040259113673 - 24 = 3040259113657 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3040259113973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6042683 + ... + 6526448.
It is an arithmetic number, because the mean of its divisors is an integer number (760067981172).
Almost surely, 23040259113673 is an apocalyptic number.
It is an amenable number.
3040259113673 is a deficient number, since it is larger than the sum of its proper divisors (12811015).
3040259113673 is a wasteful number, since it uses less digits than its factorization.
3040259113673 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12811014.
The product of its (nonzero) digits is 408240, while the sum is 44.
The spelling of 3040259113673 in words is "three trillion, forty billion, two hundred fifty-nine million, one hundred thirteen thousand, six hundred seventy-three".
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