Base | Representation |
---|---|
bin | 101100001111011101100… |
… | …100001000001010111001 |
3 | 101202122102212220011001201 |
4 | 230033131210020022321 |
5 | 344302422313114112 |
6 | 10244401544014201 |
7 | 432436312035223 |
oct | 54173544101271 |
9 | 11678385804051 |
10 | 3040259113657 |
11 | a72404012737 |
12 | 411280761361 |
13 | 19090649614c |
14 | a7213a73413 |
15 | 5413dd60257 |
hex | 2c3dd9082b9 |
3040259113657 has 2 divisors, whose sum is σ = 3040259113658. Its totient is φ = 3040259113656.
The previous prime is 3040259113637. The next prime is 3040259113667. The reversal of 3040259113657 is 7563119520403.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3019736832121 + 20522281536 = 1737739^2 + 143256^2 .
It is an emirp because it is prime and its reverse (7563119520403) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3040259113657 is a prime.
It is not a weakly prime, because it can be changed into another prime (3040259113607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520129556828 + 1520129556829.
It is an arithmetic number, because the mean of its divisors is an integer number (1520129556829).
Almost surely, 23040259113657 is an apocalyptic number.
It is an amenable number.
3040259113657 is a deficient number, since it is larger than the sum of its proper divisors (1).
3040259113657 is an equidigital number, since it uses as much as digits as its factorization.
3040259113657 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 46.
The spelling of 3040259113657 in words is "three trillion, forty billion, two hundred fifty-nine million, one hundred thirteen thousand, six hundred fifty-seven".
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