Base | Representation |
---|---|
bin | 101100010000001010011… |
… | …100101101100011001111 |
3 | 101202201101100212001221211 |
4 | 230100022130231203033 |
5 | 344310443102104320 |
6 | 10245004404035251 |
7 | 432464054506024 |
oct | 54201234554317 |
9 | 11681340761854 |
10 | 3041012144335 |
11 | a72760092840 |
12 | 411450992b27 |
13 | 1909c64b2229 |
14 | a7285a9354b |
15 | 5418500a55a |
hex | 2c40a72d8cf |
3041012144335 has 16 divisors (see below), whose sum is σ = 3981007701792. Its totient is φ = 2211619446400.
The previous prime is 3041012144293. The next prime is 3041012144347. The reversal of 3041012144335 is 5334412101403.
It is not a de Polignac number, because 3041012144335 - 215 = 3041012111567 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3041012144297 and 3041012144306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5343405 + ... + 5885065.
It is an arithmetic number, because the mean of its divisors is an integer number (248812981362).
Almost surely, 23041012144335 is an apocalyptic number.
3041012144335 is a deficient number, since it is larger than the sum of its proper divisors (939995557457).
3041012144335 is a wasteful number, since it uses less digits than its factorization.
3041012144335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 643754.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 3041012144335 its reverse (5334412101403), we get a palindrome (8375424245738).
The spelling of 3041012144335 in words is "three trillion, forty-one billion, twelve million, one hundred forty-four thousand, three hundred thirty-five".
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