Base | Representation |
---|---|
bin | 101100010000010110010… |
… | …100111101101101111111 |
3 | 101202201220020212100012201 |
4 | 230100112110331231333 |
5 | 344311400112034444 |
6 | 10245040243412331 |
7 | 432502024500655 |
oct | 54202624755577 |
9 | 11681806770181 |
10 | 3041211439999 |
11 | a728526345a7 |
12 | 4114a76840a7 |
13 | 190a28880a65 |
14 | a72a4330dd5 |
15 | 54197775dd4 |
hex | 2c41653db7f |
3041211439999 has 4 divisors (see below), whose sum is σ = 3041695947064. Its totient is φ = 3040726932936.
The previous prime is 3041211439961. The next prime is 3041211440147. The reversal of 3041211439999 is 9999341121403.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3041211439999 - 211 = 3041211437951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3041211439099) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242244117 + ... + 242256670.
It is an arithmetic number, because the mean of its divisors is an integer number (760423986766).
Almost surely, 23041211439999 is an apocalyptic number.
3041211439999 is a deficient number, since it is larger than the sum of its proper divisors (484507065).
3041211439999 is an equidigital number, since it uses as much as digits as its factorization.
3041211439999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 484507064.
The product of its (nonzero) digits is 1889568, while the sum is 55.
The spelling of 3041211439999 in words is "three trillion, forty-one billion, two hundred eleven million, four hundred thirty-nine thousand, nine hundred ninety-nine".
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