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3041312421983 = 11276482947453
BaseRepresentation
bin101100010000011100010…
…110001011100001011111
3101202202011021212202110012
4230100130112023201133
5344312101440000413
610245054252033435
7432504362023043
oct54203426134137
911682137782405
103041312421983
11a728a4636890
1241151546287b
13190a43779504
14a72b38da023
15541a15717a8
hex2c41c58b85f

3041312421983 has 4 divisors (see below), whose sum is σ = 3317795369448. Its totient is φ = 2764829474520.

The previous prime is 3041312421977. The next prime is 3041312421989. The reversal of 3041312421983 is 3891242131403.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (3041312421977) and next prime (3041312421989).

It is a cyclic number.

It is not a de Polignac number, because 3041312421983 - 234 = 3024132552799 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3041312421983.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3041312421989) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138241473716 + ... + 138241473737.

It is an arithmetic number, because the mean of its divisors is an integer number (829448842362).

Almost surely, 23041312421983 is an apocalyptic number.

3041312421983 is a deficient number, since it is larger than the sum of its proper divisors (276482947465).

3041312421983 is a wasteful number, since it uses less digits than its factorization.

3041312421983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 276482947464.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 3041312421983 in words is "three trillion, forty-one billion, three hundred twelve million, four hundred twenty-one thousand, nine hundred eighty-three".

Divisors: 1 11 276482947453 3041312421983