Base | Representation |
---|---|
bin | 101100010001000110000… |
… | …111001000101001001111 |
3 | 101202210222010100221221110 |
4 | 230101012013020221033 |
5 | 344320020324333403 |
6 | 10245252002303103 |
7 | 432530630615445 |
oct | 54210607105117 |
9 | 11683863327843 |
10 | 3042013121103 |
11 | a73124113470 |
12 | 411690057a93 |
13 | 190b259a1b88 |
14 | a733c9b6b95 |
15 | 541e2d31103 |
hex | 2c4461c8a4f |
3042013121103 has 16 divisors (see below), whose sum is σ = 4427636533632. Its totient is φ = 1842440076000.
The previous prime is 3042013121071. The next prime is 3042013121129. The reversal of 3042013121103 is 3011213102403.
It is not a de Polignac number, because 3042013121103 - 25 = 3042013121071 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3042013121103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3042013121143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30054708 + ... + 30155753.
It is an arithmetic number, because the mean of its divisors is an integer number (276727283352).
Almost surely, 23042013121103 is an apocalyptic number.
3042013121103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3042013121103 is a deficient number, since it is larger than the sum of its proper divisors (1385623412529).
3042013121103 is a wasteful number, since it uses less digits than its factorization.
3042013121103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60212006.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3042013121103 its reverse (3011213102403), we get a palindrome (6053226223506).
The spelling of 3042013121103 in words is "three trillion, forty-two billion, thirteen million, one hundred twenty-one thousand, one hundred three".
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