Search a number
-
+
30453000113 = 279110911143
BaseRepresentation
bin11100010111001000…
…111110011110110001
32220121022200200201002
4130113020332132301
5444331432000423
621553453251345
72125440141614
oct342710763661
986538620632
1030453000113
1111a07a19798
125a9a793b55
132b441a24c3
14168c68817b
15bd37ab228
hex71723e7b1

30453000113 has 4 divisors (see below), whose sum is σ = 30463914048. Its totient is φ = 30442086180.

The previous prime is 30453000103. The next prime is 30453000119. The reversal of 30453000113 is 31100035403.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31100035403 = 37383378111.

It is a cyclic number.

It is not a de Polignac number, because 30453000113 - 210 = 30452999089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30453000119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5452781 + ... + 5458362.

It is an arithmetic number, because the mean of its divisors is an integer number (7615978512).

Almost surely, 230453000113 is an apocalyptic number.

It is an amenable number.

30453000113 is a deficient number, since it is larger than the sum of its proper divisors (10913935).

30453000113 is a wasteful number, since it uses less digits than its factorization.

30453000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10913934.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 30453000113 its reverse (31100035403), we get a palindrome (61553035516).

The spelling of 30453000113 in words is "thirty billion, four hundred fifty-three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 2791 10911143 30453000113