Base | Representation |
---|---|
bin | 1101110111101011001001… |
… | …10100011001001011010001 |
3 | 10222222210111011021110000021 |
4 | 12323311210310121023101 |
5 | 12444204010040200410 |
6 | 144511342351223441 |
7 | 6265366506215620 |
oct | 673654464311321 |
9 | 128883434243007 |
10 | 30500254225105 |
11 | 979a0a3408645 |
12 | 35071a1517b81 |
13 | 140321414b882 |
14 | 7763122696b7 |
15 | 37d5acdc7eda |
hex | 1bbd64d192d1 |
30500254225105 has 16 divisors (see below), whose sum is σ = 41829009978240. Its totient is φ = 20914415091072.
The previous prime is 30500254225073. The next prime is 30500254225139. The reversal of 30500254225105 is 50152245200503.
It is a cyclic number.
It is not a de Polignac number, because 30500254225105 - 25 = 30500254225073 is a prime.
It is a super-2 number, since 2×305002542251052 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29679082 + ... + 30689548.
It is an arithmetic number, because the mean of its divisors is an integer number (2614313123640).
Almost surely, 230500254225105 is an apocalyptic number.
30500254225105 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
30500254225105 is a deficient number, since it is larger than the sum of its proper divisors (11328755753135).
30500254225105 is a wasteful number, since it uses less digits than its factorization.
30500254225105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1872888.
The product of its (nonzero) digits is 60000, while the sum is 34.
Adding to 30500254225105 its reverse (50152245200503), we get a palindrome (80652499425608).
The spelling of 30500254225105 in words is "thirty trillion, five hundred billion, two hundred fifty-four million, two hundred twenty-five thousand, one hundred five".
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