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30502441433011 = 194153738790453
BaseRepresentation
bin1101110111101111001110…
…01011111011011110110011
311000000000010120220010012111
412323313213023323132303
512444223000001324021
6144512343402510151
76265504635166222
oct673674713733663
9130000116803174
1030502441433011
1197a0015aa0289
1235076b1b05357
1314034a2321832
1477647c936cb9
1537d689e198e1
hex1bbde72fb7b3

30502441433011 has 16 divisors (see below), whose sum is σ = 33511534993440. Its totient is φ = 27660314522880.

The previous prime is 30502441432993. The next prime is 30502441433041. The reversal of 30502441433011 is 11033414420503.

It is not a de Polignac number, because 30502441433011 - 217 = 30502441301939 is a prime.

It is a super-2 number, since 2×305024414330112 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30502441433041) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 369353940 + ... + 369436513.

It is an arithmetic number, because the mean of its divisors is an integer number (2094470937090).

Almost surely, 230502441433011 is an apocalyptic number.

30502441433011 is a deficient number, since it is larger than the sum of its proper divisors (3009093560429).

30502441433011 is a wasteful number, since it uses less digits than its factorization.

30502441433011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 738790566.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 30502441433011 its reverse (11033414420503), we get a palindrome (41535855853514).

The spelling of 30502441433011 in words is "thirty trillion, five hundred two billion, four hundred forty-one million, four hundred thirty-three thousand, eleven".

Divisors: 1 19 41 53 779 1007 2173 41287 738790453 14037018607 30290408573 39155894009 575517762887 743961986171 1605391654369 30502441433011