Base | Representation |
---|---|
bin | 100010101011111010001111… |
… | …0011010101010001110000111 |
3 | 1111000021110212002012100212002 |
4 | 1011113310132122222032013 |
5 | 304442243101120023421 |
6 | 3000521545403215515 |
7 | 121156620341036444 |
oct | 10527643632521607 |
9 | 1430243762170762 |
10 | 305102102111111 |
11 | 89240090712298 |
12 | 2a2769b881759b |
13 | 1013200a655536 |
14 | 554b0404b89cb |
15 | 2541614aecb0b |
hex | 1157d1e6aa387 |
305102102111111 has 4 divisors (see below), whose sum is σ = 321160107485400. Its totient is φ = 289044096736824.
The previous prime is 305102102111071. The next prime is 305102102111113. The reversal of 305102102111111 is 111111201201503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-305102102111111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (305102102111113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8029002687116 + ... + 8029002687153.
It is an arithmetic number, because the mean of its divisors is an integer number (80290026871350).
Almost surely, 2305102102111111 is an apocalyptic number.
305102102111111 is a deficient number, since it is larger than the sum of its proper divisors (16058005374289).
305102102111111 is a wasteful number, since it uses less digits than its factorization.
305102102111111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16058005374288.
The product of its (nonzero) digits is 60, while the sum is 20.
Adding to 305102102111111 its reverse (111111201201503), we get a palindrome (416213303312614).
The spelling of 305102102111111 in words is "three hundred five trillion, one hundred two billion, one hundred two million, one hundred eleven thousand, one hundred eleven".
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