Base | Representation |
---|---|
bin | 101100011001110110110… |
… | …011100111001010111011 |
3 | 101210201020201010000021110 |
4 | 230121312303213022323 |
5 | 344443302011141220 |
6 | 10253445241011403 |
7 | 433313014141032 |
oct | 54316663471273 |
9 | 11721221100243 |
10 | 3051420021435 |
11 | a77111062965 |
12 | 413476483b63 |
13 | 19199483b4a6 |
14 | a799206b719 |
15 | 54593ad5be0 |
hex | 2c676ce72bb |
3051420021435 has 8 divisors (see below), whose sum is σ = 4882272034320. Its totient is φ = 1627424011424.
The previous prime is 3051420021431. The next prime is 3051420021469. The reversal of 3051420021435 is 5341200241503.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3051420021435 - 22 = 3051420021431 is a prime.
It is a super-2 number, since 2×30514200214352 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3051420021431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101714000700 + ... + 101714000729.
It is an arithmetic number, because the mean of its divisors is an integer number (610284004290).
Almost surely, 23051420021435 is an apocalyptic number.
3051420021435 is a deficient number, since it is larger than the sum of its proper divisors (1830852012885).
3051420021435 is a wasteful number, since it uses less digits than its factorization.
3051420021435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 203428001437.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 3051420021435 its reverse (5341200241503), we get a palindrome (8392620262938).
The spelling of 3051420021435 in words is "three trillion, fifty-one billion, four hundred twenty million, twenty-one thousand, four hundred thirty-five".
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