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305142314332399 = 1988391534620041
BaseRepresentation
bin100010101100001100111101…
…1010000000111000011101111
31111000102022122112120212020021
41011120121323100013003233
5304443422424432114044
63000552235522503011
7121162543003215265
oct10530317320070357
91430368575525207
10305142314332399
1189256146440325
122a28275b804a67
1310135a48680a0b
14554cd76d2a435
1525426ba054e84
hex115867b4070ef

305142314332399 has 4 divisors (see below), whose sum is σ = 305143849151280. Its totient is φ = 305140779513520.

The previous prime is 305142314332253. The next prime is 305142314332403. The reversal of 305142314332399 is 993233413241503.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 305142314332399 - 213 = 305142314324207 is a prime.

It is a super-2 number, since 2×3051423143323992 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (305142314332699) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 767111182 + ... + 767508859.

It is an arithmetic number, because the mean of its divisors is an integer number (76285962287820).

Almost surely, 2305142314332399 is an apocalyptic number.

305142314332399 is a deficient number, since it is larger than the sum of its proper divisors (1534818881).

305142314332399 is a wasteful number, since it uses less digits than its factorization.

305142314332399 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1534818880.

The product of its (nonzero) digits is 6298560, while the sum is 52.

The spelling of 305142314332399 in words is "three hundred five trillion, one hundred forty-two billion, three hundred fourteen million, three hundred thirty-two thousand, three hundred ninety-nine".

Divisors: 1 198839 1534620041 305142314332399