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30530000253 = 310176666751
BaseRepresentation
bin11100011011101110…
…101101010101111101
32220210200120201001010
4130123232231111331
51000011140002003
622005243505433
72130363502044
oct343356552575
986720521033
1030530000253
1111a47431075
125b00528279
132b5712230c
1416989ad55b
15bda41b003
hex71bbad57d

30530000253 has 4 divisors (see below), whose sum is σ = 40706667008. Its totient is φ = 20353333500.

The previous prime is 30530000251. The next prime is 30530000321. The reversal of 30530000253 is 35200003503.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 30530000253 - 21 = 30530000251 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30530000251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5088333373 + ... + 5088333378.

It is an arithmetic number, because the mean of its divisors is an integer number (10176666752).

Almost surely, 230530000253 is an apocalyptic number.

It is an amenable number.

30530000253 is a deficient number, since it is larger than the sum of its proper divisors (10176666755).

30530000253 is a wasteful number, since it uses less digits than its factorization.

30530000253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10176666754.

The product of its (nonzero) digits is 1350, while the sum is 21.

Adding to 30530000253 its reverse (35200003503), we get a palindrome (65730003756).

The spelling of 30530000253 in words is "thirty billion, five hundred thirty million, two hundred fifty-three", and thus it is an aban number.

Divisors: 1 3 10176666751 30530000253