Base | Representation |
---|---|
bin | 1101111000101001010111… |
… | …00100111100001010001111 |
3 | 11000002222200211010001101021 |
4 | 12330110223210330022033 |
5 | 13000230410311024101 |
6 | 144534544500055011 |
7 | 6300661254264145 |
oct | 674245344741217 |
9 | 130088624101337 |
10 | 30533653611151 |
11 | 98022824a8729 |
12 | 3511762994467 |
13 | 14064078831b2 |
14 | 777b9dd61595 |
15 | 37e3b51875a1 |
hex | 1bc52b93c28f |
30533653611151 has 4 divisors (see below), whose sum is σ = 30756526995312. Its totient is φ = 30310780226992.
The previous prime is 30533653611137. The next prime is 30533653611163. The reversal of 30533653611151 is 15111635633503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30533653611151 - 235 = 30499293872783 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 30533653611098 and 30533653611107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30533653611101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111436691875 + ... + 111436692148.
It is an arithmetic number, because the mean of its divisors is an integer number (7689131748828).
Almost surely, 230533653611151 is an apocalyptic number.
30533653611151 is a deficient number, since it is larger than the sum of its proper divisors (222873384161).
30533653611151 is a wasteful number, since it uses less digits than its factorization.
30533653611151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222873384160.
The product of its (nonzero) digits is 364500, while the sum is 43.
The spelling of 30533653611151 in words is "thirty trillion, five hundred thirty-three billion, six hundred fifty-three million, six hundred eleven thousand, one hundred fifty-one".
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