Base | Representation |
---|---|
bin | 101100011011110011100… |
… | …100111101010110110001 |
3 | 101210220122121001012201202 |
4 | 230123303210331112301 |
5 | 400012043403112040 |
6 | 10254433055540545 |
7 | 433415623034513 |
oct | 54336344752661 |
9 | 11726577035652 |
10 | 3053513332145 |
11 | a77a95742211 |
12 | 41395b52a755 |
13 | 191c39426693 |
14 | a7b10095bb3 |
15 | 5466777b015 |
hex | 2c6f393d5b1 |
3053513332145 has 16 divisors (see below), whose sum is σ = 3670218511488. Its totient is φ = 2438809589760.
The previous prime is 3053513332043. The next prime is 3053513332153. The reversal of 3053513332145 is 5412333153503.
It is not a de Polignac number, because 3053513332145 - 234 = 3036333462961 is a prime.
It is a super-2 number, since 2×30535133321452 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3053513332099 and 3053513332108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52811942 + ... + 52869728.
It is an arithmetic number, because the mean of its divisors is an integer number (229388656968).
Almost surely, 23053513332145 is an apocalyptic number.
It is an amenable number.
3053513332145 is a deficient number, since it is larger than the sum of its proper divisors (616705179343).
3053513332145 is a wasteful number, since it uses less digits than its factorization.
3053513332145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74920.
The product of its (nonzero) digits is 243000, while the sum is 38.
Adding to 3053513332145 its reverse (5412333153503), we get a palindrome (8465846485648).
The spelling of 3053513332145 in words is "three trillion, fifty-three billion, five hundred thirteen million, three hundred thirty-two thousand, one hundred forty-five".
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