Base | Representation |
---|---|
bin | 101100011011110100100… |
… | …101001100111001110111 |
3 | 101210220200202201211002212 |
4 | 230123310211030321313 |
5 | 400012112211014142 |
6 | 10254434500524035 |
7 | 433416216135404 |
oct | 54336445147167 |
9 | 11726622654085 |
10 | 3053530173047 |
11 | a77aa41a5012 |
12 | 4139650b061b |
13 | 191c3ca71c03 |
14 | a7b123db2ab |
15 | 54668ea5d82 |
hex | 2c6f494ce77 |
3053530173047 has 4 divisors (see below), whose sum is σ = 3072979409976. Its totient is φ = 3034080936120.
The previous prime is 3053530173041. The next prime is 3053530173077. The reversal of 3053530173047 is 7403710353503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3053530173047 - 230 = 3052456431223 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3053530172995 and 3053530173013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3053530173041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9724618229 + ... + 9724618542.
It is an arithmetic number, because the mean of its divisors is an integer number (768244852494).
Almost surely, 23053530173047 is an apocalyptic number.
3053530173047 is a deficient number, since it is larger than the sum of its proper divisors (19449236929).
3053530173047 is a wasteful number, since it uses less digits than its factorization.
3053530173047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19449236928.
The product of its (nonzero) digits is 396900, while the sum is 41.
The spelling of 3053530173047 in words is "three trillion, fifty-three billion, five hundred thirty million, one hundred seventy-three thousand, forty-seven".
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