Base | Representation |
---|---|
bin | 11100011100101000… |
… | …000011101110100111 |
3 | 2220211201212111200011 |
4 | 130130220003232213 |
5 | 1000024012043101 |
6 | 22010542031051 |
7 | 2130635335462 |
oct | 343450035647 |
9 | 86751774604 |
10 | 30545034151 |
11 | 11a5496a285 |
12 | 5b05578487 |
13 | 2b5a287208 |
14 | 169a9a42d9 |
15 | bdb8da751 |
hex | 71ca03ba7 |
30545034151 has 4 divisors (see below), whose sum is σ = 30547702432. Its totient is φ = 30542365872.
The previous prime is 30545034127. The next prime is 30545034193. The reversal of 30545034151 is 15143054503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30545034151 - 217 = 30544903079 is a prime.
It is a super-2 number, since 2×305450341512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30545034251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1316895 + ... + 1339888.
It is an arithmetic number, because the mean of its divisors is an integer number (7636925608).
Almost surely, 230545034151 is an apocalyptic number.
30545034151 is a deficient number, since it is larger than the sum of its proper divisors (2668281).
30545034151 is a wasteful number, since it uses less digits than its factorization.
30545034151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2668280.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 30545034151 its reverse (15143054503), we get a palindrome (45688088654).
The spelling of 30545034151 in words is "thirty billion, five hundred forty-five million, thirty-four thousand, one hundred fifty-one".
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