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30552254022434 = 215276127011217
BaseRepresentation
bin1101111001001100000000…
…01111111000001100100010
311000011202201010001211211212
412330212000033320030202
513001032004012204214
6144551302311310122
76302220223210364
oct674460017701442
9130152633054755
1030552254022434
11980a157999a61
12351529407b342
1314080b02c4611
14778a46400d34
1537eb030e053e
hex1bc9803f8322

30552254022434 has 4 divisors (see below), whose sum is σ = 45828381033654. Its totient is φ = 15276127011216.

The previous prime is 30552254022373. The next prime is 30552254022449. The reversal of 30552254022434 is 43422045225503.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 27084707264209 + 3467546758225 = 5204297^2 + 1862135^2 .

It is a junction number, because it is equal to n+sod(n) for n = 30552254022391 and 30552254022400.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7638063505607 + ... + 7638063505610.

Almost surely, 230552254022434 is an apocalyptic number.

30552254022434 is a deficient number, since it is larger than the sum of its proper divisors (15276127011220).

30552254022434 is a wasteful number, since it uses less digits than its factorization.

30552254022434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15276127011219.

The product of its (nonzero) digits is 1152000, while the sum is 41.

Adding to 30552254022434 its reverse (43422045225503), we get a palindrome (73974299247937).

The spelling of 30552254022434 in words is "thirty trillion, five hundred fifty-two billion, two hundred fifty-four million, twenty-two thousand, four hundred thirty-four".

Divisors: 1 2 15276127011217 30552254022434