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30555012000000 = 2835622911119
BaseRepresentation
bin1101111001010001001001…
…01000101110100100000000
311000012000211022200121211010
412330220210220232210000
513001103131033000000
6144552440112320520
76302345452505325
oct674504450564400
9130160738617733
1030555012000000
119810342785364
123515923843140
13140842c7ca5c7
14778c28806b4c
1537ec152c8d50
hex1bca24a2e900

30555012000000 has 504 divisors, whose sum is σ = 102102880566400. Its totient is φ = 8111692800000.

The previous prime is 30555011999983. The next prime is 30555012000031. The reversal of 30555012000000 is 21055503.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2747994441 + ... + 2748005559.

Almost surely, 230555012000000 is an apocalyptic number.

30555012000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 30555012000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (51051440283200).

30555012000000 is an abundant number, since it is smaller than the sum of its proper divisors (71547868566400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

30555012000000 is an frugal number, since it uses more digits than its factorization.

30555012000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11397 (or 11358 counting only the distinct ones).

The product of its (nonzero) digits is 750, while the sum is 21.

Adding to 30555012000000 its reverse (21055503), we get a palindrome (30555033055503).

The spelling of 30555012000000 in words is "thirty trillion, five hundred fifty-five billion, twelve million", and thus it is an aban number.