Base | Representation |
---|---|
bin | 1101111011111111001001… |
… | …00000011001010010100011 |
3 | 11000111221221110101200220220 |
4 | 12331333210200121102203 |
5 | 13004120433342320103 |
6 | 145103405304534123 |
7 | 6312163360066413 |
oct | 675774440312243 |
9 | 130457843350826 |
10 | 30648425354403 |
11 | 9846a191230aa |
12 | 352ba53781343 |
13 | 141419883cccc |
14 | 77d56ab8a643 |
15 | 382381149c53 |
hex | 1bdfe48194a3 |
30648425354403 has 32 divisors (see below), whose sum is σ = 43890586822656. Its totient is φ = 18954196005888.
The previous prime is 30648425354399. The next prime is 30648425354441. The reversal of 30648425354403 is 30445352484603.
It is a Cunningham number, because it is equal to 55361022-1.
It is not a de Polignac number, because 30648425354403 - 22 = 30648425354399 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is not an unprimeable number, because it can be changed into a prime (30648425354453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2768050 + ... + 8304152.
It is an arithmetic number, because the mean of its divisors is an integer number (1371580838208).
Almost surely, 230648425354403 is an apocalyptic number.
30648425354403 is a deficient number, since it is larger than the sum of its proper divisors (13242161468253).
30648425354403 is a wasteful number, since it uses less digits than its factorization.
30648425354403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5537683.
The product of its (nonzero) digits is 16588800, while the sum is 51.
The spelling of 30648425354403 in words is "thirty trillion, six hundred forty-eight billion, four hundred twenty-five million, three hundred fifty-four thousand, four hundred three".
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