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31002212013 = 3149147147149
BaseRepresentation
bin11100110111111000…
…000011011010101101
32222000121010112210120
4130313320003122231
51001443031241023
622124152555153
72145156311523
oct346770033255
988017115716
1031002212013
1112169a38823
1260126b2ab9
132c00bc8066
1417015b0313
15c16ae58e3
hex737e036ad

31002212013 has 16 divisors (see below), whose sum is σ = 41642880000. Its totient is φ = 20515037760.

The previous prime is 31002211987. The next prime is 31002212077. The reversal of 31002212013 is 31021220013.

It is not a de Polignac number, because 31002212013 - 216 = 31002146477 is a prime.

It is a super-2 number, since 2×310022120132 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31002211983 and 31002212001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31002212413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 633963 + ... + 681111.

It is an arithmetic number, because the mean of its divisors is an integer number (2602680000).

Almost surely, 231002212013 is an apocalyptic number.

It is an amenable number.

31002212013 is a deficient number, since it is larger than the sum of its proper divisors (10640667987).

31002212013 is a wasteful number, since it uses less digits than its factorization.

31002212013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48772.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 31002212013 its reverse (31021220013), we get a palindrome (62023432026).

The spelling of 31002212013 in words is "thirty-one billion, two million, two hundred twelve thousand, thirteen".

Divisors: 1 3 149 447 1471 4413 47149 141447 219179 657537 7025201 21075603 69356179 208068537 10334070671 31002212013