Base | Representation |
---|---|
bin | 101101000111011000111… |
… | …101000101011010000000 |
3 | 101222101110000200220110220 |
4 | 231013120331011122000 |
5 | 401243414143441000 |
6 | 10332132515023040 |
7 | 436663414224540 |
oct | 55073075053200 |
9 | 11871400626426 |
10 | 3100311312000 |
11 | a9591aa02121 |
12 | 420a3bb9aa80 |
13 | 19648699b216 |
14 | aa0ad433320 |
15 | 559a5e741a0 |
hex | 2d1d8f45680 |
3100311312000 has 512 divisors, whose sum is σ = 12256466227200. Its totient is φ = 677830348800.
The previous prime is 3100311311941. The next prime is 3100311312011. The reversal of 3100311312000 is 2131130013.
It is a super-2 number, since 2×31003113120002 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7527411 + ... + 7928589.
It is an arithmetic number, because the mean of its divisors is an integer number (23938410600).
Almost surely, 23100311312000 is an apocalyptic number.
3100311312000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3100311312000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6128233113600).
3100311312000 is an abundant number, since it is smaller than the sum of its proper divisors (9156154915200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3100311312000 is a wasteful number, since it uses less digits than its factorization.
3100311312000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401241 (or 401219 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 3100311312000 its reverse (2131130013), we get a palindrome (3102442442013).
The spelling of 3100311312000 in words is "three trillion, one hundred billion, three hundred eleven million, three hundred twelve thousand".
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