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31004040133 = 1161254918127
BaseRepresentation
bin11100110111111111…
…000001101111000101
32222000201120102111201
4130313333001233011
51001444013241013
622124300102501
72145210664363
oct346777015705
988021512451
1031004040133
111216aa77270
126013234a31
132c013b81a1
141701928633
15c16d573dd
hex737fc1bc5

31004040133 has 16 divisors (see below), whose sum is σ = 34392441600. Its totient is φ = 27711028800.

The previous prime is 31004040121. The next prime is 31004040149. The reversal of 31004040133 is 33104040013.

It is a cyclic number.

It is not a de Polignac number, because 31004040133 - 217 = 31003909061 is a prime.

It is a super-2 number, since 2×310040401332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 31004040133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31004040833) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1701316 + ... + 1719442.

It is an arithmetic number, because the mean of its divisors is an integer number (2149527600).

Almost surely, 231004040133 is an apocalyptic number.

It is an amenable number.

31004040133 is a deficient number, since it is larger than the sum of its proper divisors (3388401467).

31004040133 is a wasteful number, since it uses less digits than its factorization.

31004040133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20748.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 31004040133 its reverse (33104040013), we get a palindrome (64108080146).

The spelling of 31004040133 in words is "thirty-one billion, four million, forty thousand, one hundred thirty-three".

Divisors: 1 11 61 671 2549 18127 28039 155489 199397 1105747 1710379 12163217 46205723 508262953 2818549103 31004040133