Base | Representation |
---|---|
bin | 11100111000111111… |
… | …101111010011101101 |
3 | 2222001220111021120120 |
4 | 130320333233103231 |
5 | 1002012334112023 |
6 | 22130103435153 |
7 | 2145505116636 |
oct | 347077572355 |
9 | 88056437516 |
10 | 31021004013 |
11 | 121796034aa |
12 | 6018a55ab9 |
13 | 2c04a7769c |
14 | 1703ca288d |
15 | c185a88e3 |
hex | 738fef4ed |
31021004013 has 8 divisors (see below), whose sum is σ = 41364643008. Its totient is φ = 20679017184.
The previous prime is 31021003927. The next prime is 31021004029. The reversal of 31021004013 is 31040012013.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31021004013 - 213 = 31020995821 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 31021003983 and 31021004001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31021004033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 368545 + ... + 444822.
It is an arithmetic number, because the mean of its divisors is an integer number (5170580376).
Almost surely, 231021004013 is an apocalyptic number.
It is an amenable number.
31021004013 is a deficient number, since it is larger than the sum of its proper divisors (10343638995).
31021004013 is a wasteful number, since it uses less digits than its factorization.
31021004013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 826083.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 31021004013 its reverse (31040012013), we get a palindrome (62061016026).
The spelling of 31021004013 in words is "thirty-one billion, twenty-one million, four thousand, thirteen".
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