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3102131114 = 21551065557
BaseRepresentation
bin1011100011100110…
…1100001110101010
322000012012120212222
42320321230032222
522323121143424
61231453234042
7136605452015
oct27071541652
98005176788
103102131114
111352088025
12726a92922
133a58c3054
14215dd037c
15132519e5e
hexb8e6c3aa

3102131114 has 4 divisors (see below), whose sum is σ = 4653196674. Its totient is φ = 1551065556.

The previous prime is 3102131113. The next prime is 3102131119. The reversal of 3102131114 is 4111312013.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2923240489 + 178890625 = 54067^2 + 13375^2 .

It is a junction number, because it is equal to n+sod(n) for n = 3102131092 and 3102131101.

It is not an unprimeable number, because it can be changed into a prime (3102131111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775532777 + ... + 775532780.

Almost surely, 23102131114 is an apocalyptic number.

3102131114 is a deficient number, since it is larger than the sum of its proper divisors (1551065560).

3102131114 is a wasteful number, since it uses less digits than its factorization.

3102131114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1551065559.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 3102131114 is about 55696.7783089830. The cubic root of 3102131114 is about 1458.4337858235.

Adding to 3102131114 its reverse (4111312013), we get a palindrome (7213443127).

The spelling of 3102131114 in words is "three billion, one hundred two million, one hundred thirty-one thousand, one hundred fourteen".

Divisors: 1 2 1551065557 3102131114