Base | Representation |
---|---|
bin | 11100111001100111… |
… | …011010011110010010 |
3 | 2222002122001200021100 |
4 | 130321213122132102 |
5 | 1002023014420214 |
6 | 22131114405230 |
7 | 2145662404602 |
oct | 347147323622 |
9 | 88078050240 |
10 | 31031404434 |
11 | 12184467498 |
12 | 6020430816 |
13 | 2c06c79594 |
14 | 170540cc02 |
15 | c19460309 |
hex | 7399da792 |
31031404434 has 12 divisors (see below), whose sum is σ = 67234709646. Its totient is φ = 10343801472.
The previous prime is 31031404433. The next prime is 31031404483. The reversal of 31031404434 is 43440413013.
31031404434 is a `hidden beast` number, since 310 + 314 + 0 + 4 + 4 + 34 = 666.
It can be written as a sum of positive squares in only one way, i.e., 16668101025 + 14363303409 = 129105^2 + 119847^2 .
It is a super-2 number, since 2×310314044342 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31031404398 and 31031404407.
It is not an unprimeable number, because it can be changed into a prime (31031404433) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 861983439 + ... + 861983474.
Almost surely, 231031404434 is an apocalyptic number.
31031404434 is an abundant number, since it is smaller than the sum of its proper divisors (36203305212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31031404434 is a wasteful number, since it uses less digits than its factorization.
31031404434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1723966921 (or 1723966918 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 31031404434 its reverse (43440413013), we get a palindrome (74471817447).
The spelling of 31031404434 in words is "thirty-one billion, thirty-one million, four hundred four thousand, four hundred thirty-four".
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