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3104130021 = 31034710007
BaseRepresentation
bin1011100100000101…
…0100001111100101
322000022222010212120
42321001110033211
522324124130041
61232004140153
7136631445516
oct27101241745
98008863776
103104130021
111353222913
12727697659
133a6142b35
14216390a0d
151327b2366
hexb90543e5

3104130021 has 4 divisors (see below), whose sum is σ = 4138840032. Its totient is φ = 2069420012.

The previous prime is 3104129953. The next prime is 3104130047. The reversal of 3104130021 is 1200314013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3104130021 - 215 = 3104097253 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3104130091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 517355001 + ... + 517355006.

It is an arithmetic number, because the mean of its divisors is an integer number (1034710008).

Almost surely, 23104130021 is an apocalyptic number.

It is an amenable number.

3104130021 is a deficient number, since it is larger than the sum of its proper divisors (1034710011).

3104130021 is a wasteful number, since it uses less digits than its factorization.

3104130021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1034710010.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 3104130021 is about 55714.7199669890. The cubic root of 3104130021 is about 1458.7469734842.

Adding to 3104130021 its reverse (1200314013), we get a palindrome (4304444034).

The spelling of 3104130021 in words is "three billion, one hundred four million, one hundred thirty thousand, twenty-one".

Divisors: 1 3 1034710007 3104130021