31100113133 has 4 divisors (see below), whose sum is σ = 31100502300. Its totient is φ = 31099723968.

The previous prime is 31100113127. The next prime is 31100113147. The reversal of 31100113133 is 33131100113.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 33131100113 = 108649 ⋅304937.

It can be written as a sum of positive squares in 2 ways, for example, as 22927410724 + 8172702409 = 151418^2 + 90403^2 .

It is a cyclic number.

It is not a de Polignac number, because 31100113133 - 2⁴ = 31100113117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31100113433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26060 + ... + 250757.

It is an arithmetic number, because the mean of its divisors is an integer number (7775125575).

Almost surely, 2^31100113133 is an apocalyptic number.

It is an amenable number.

31100113133 is a deficient number, since it is larger than the sum of its proper divisors (389167).

31100113133 is a wasteful number, since it uses less digits than its factorization.

31100113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 389166.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 31100113133 its reverse (33131100113), we get a palindrome (64231213246).

The spelling of 31100113133 in words is "thirty-one billion, one hundred million, one hundred thirteen thousand, one hundred thirty-three".