3110012113 has 32 divisors (see below), whose sum is σ = 3679270560. Its totient is φ = 2604220416.

The previous prime is 3110012107. The next prime is 3110012149. The reversal of 3110012113 is 3112100113.

3110012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 16 ways, for example, as 577104529 + 2532907584 = 24023^2 + 50328^2 .

It is not a de Polignac number, because 3110012113 - 2²¹ = 3107914961 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a junction number, because it is equal to n+sod(n) for n = 3110012093 and 3110012102.

It is not an unprimeable number, because it can be changed into a prime (3110012153) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5389681 + ... + 5390257.

It is an arithmetic number, because the mean of its divisors is an integer number (114977205).

Almost surely, 2^3110012113 is an apocalyptic number.

It is an amenable number.

3110012113 is a deficient number, since it is larger than the sum of its proper divisors (569258447).

3110012113 is an equidigital number, since it uses as much as digits as its factorization.

3110012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 694 (or 636 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 3110012113 is about 55767.4825772152. The cubic root of 3110012113 is about 1459.6677972205.

Adding to 3110012113 its reverse (3112100113), we get a palindrome (6222112226).

The spelling of 3110012113 in words is "three billion, one hundred ten million, twelve thousand, one hundred thirteen".