Base | Representation |
---|---|
bin | 1001000011010010001… |
… | …11011110100001010101 |
3 | 1002201202012122112220221 |
4 | 10201221013132201111 |
5 | 20043412302304023 |
6 | 354512203154341 |
7 | 31316620456561 |
oct | 4415107364125 |
9 | 1081665575827 |
10 | 311001213013 |
11 | 10a993093487 |
12 | 503358159b1 |
13 | 2343408c3ca |
14 | 110a424a6a1 |
15 | 81533dc85d |
hex | 48691de855 |
311001213013 has 4 divisors (see below), whose sum is σ = 311813227008. Its totient is φ = 310189199020.
The previous prime is 311001212971. The next prime is 311001213053. The reversal of 311001213013 is 310312100113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311001213013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311001213053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406006423 + ... + 406007188.
It is an arithmetic number, because the mean of its divisors is an integer number (77953306752).
Almost surely, 2311001213013 is an apocalyptic number.
It is an amenable number.
311001213013 is a deficient number, since it is larger than the sum of its proper divisors (812013995).
311001213013 is an equidigital number, since it uses as much as digits as its factorization.
311001213013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 812013994.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 311001213013 its reverse (310312100113), we get a palindrome (621313313126).
The spelling of 311001213013 in words is "three hundred eleven billion, one million, two hundred thirteen thousand, thirteen".
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