Base | Representation |
---|---|
bin | 1001000011010011011… |
… | …01101001101011110101 |
3 | 1002201202220110222012222 |
4 | 10201221231221223311 |
5 | 20043422333021323 |
6 | 354513201452125 |
7 | 31320101516231 |
oct | 4415155515365 |
9 | 1081686428188 |
10 | 311011220213 |
11 | 10a9987a8aa1 |
12 | 50339041045 |
13 | 23436184325 |
14 | 110a56d35c1 |
15 | 81542179c8 |
hex | 4869b69af5 |
311011220213 has 4 divisors (see below), whose sum is σ = 311012832288. Its totient is φ = 311009608140.
The previous prime is 311011220159. The next prime is 311011220249. The reversal of 311011220213 is 312022110113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 311011220213 - 28 = 311011219957 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 311011220191 and 311011220200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311011226213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469931 + ... + 918072.
It is an arithmetic number, because the mean of its divisors is an integer number (77753208072).
Almost surely, 2311011220213 is an apocalyptic number.
It is an amenable number.
311011220213 is a deficient number, since it is larger than the sum of its proper divisors (1612075).
311011220213 is a wasteful number, since it uses less digits than its factorization.
311011220213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1612074.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 311011220213 its reverse (312022110113), we get a palindrome (623033330326).
The spelling of 311011220213 in words is "three hundred eleven billion, eleven million, two hundred twenty thousand, two hundred thirteen".
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