Base | Representation |
---|---|
bin | 101101010000100010001… |
… | …101100011010011010001 |
3 | 102000022210022212011222022 |
4 | 231100202031203103101 |
5 | 401424021324100423 |
6 | 10340435114021225 |
7 | 440461633235204 |
oct | 55204215432321 |
9 | 12008708764868 |
10 | 3110130300113 |
11 | a99aa9523231 |
12 | 422920417815 |
13 | 19739001c065 |
14 | aa76151793b |
15 | 55d7cec8dc8 |
hex | 2d4223634d1 |
3110130300113 has 16 divisors (see below), whose sum is σ = 3293582947200. Its totient is φ = 2928704428800.
The previous prime is 3110130300089. The next prime is 3110130300143. The reversal of 3110130300113 is 3110030310113.
It is a cyclic number.
It is not a de Polignac number, because 3110130300113 - 212 = 3110130296017 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 3110130300091 and 3110130300100.
It is not an unprimeable number, because it can be changed into a prime (3110130300143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1510388 + ... + 2915738.
It is an arithmetic number, because the mean of its divisors is an integer number (205848934200).
Almost surely, 23110130300113 is an apocalyptic number.
It is an amenable number.
3110130300113 is a deficient number, since it is larger than the sum of its proper divisors (183452647087).
3110130300113 is a wasteful number, since it uses less digits than its factorization.
3110130300113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1406072.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 3110130300113 its reverse (3110030310113), we get a palindrome (6220160610226).
The spelling of 3110130300113 in words is "three trillion, one hundred ten billion, one hundred thirty million, three hundred thousand, one hundred thirteen".
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