Base | Representation |
---|---|
bin | 1001000011010011110… |
… | …00010000011100010001 |
3 | 1002201210002201012220220 |
4 | 10201221320100130101 |
5 | 20043424041003101 |
6 | 354513341223253 |
7 | 31320134245566 |
oct | 4415170203421 |
9 | 1081702635826 |
10 | 311014000401 |
11 | 10a99a327875 |
12 | 50339b61b29 |
13 | 23436918900 |
14 | 110a5c1886d |
15 | 81545b6636 |
hex | 4869e10711 |
311014000401 has 24 divisors (see below), whose sum is σ = 449450348256. Its totient is φ = 191217461760.
The previous prime is 311014000393. The next prime is 311014000403. The reversal of 311014000401 is 104000410113.
It is not a de Polignac number, because 311014000401 - 23 = 311014000393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311014000403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 272001 + ... + 834273.
It is an arithmetic number, because the mean of its divisors is an integer number (18727097844).
Almost surely, 2311014000401 is an apocalyptic number.
It is an amenable number.
311014000401 is a deficient number, since it is larger than the sum of its proper divisors (138436347855).
311014000401 is a wasteful number, since it uses less digits than its factorization.
311014000401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563393 (or 563380 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 311014000401 its reverse (104000410113), we get a palindrome (415014410514).
The spelling of 311014000401 in words is "three hundred eleven billion, fourteen million, four hundred one", and thus it is an aban number.
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