Base | Representation |
---|---|
bin | 101101010000100110100… |
… | …010111000110100001010 |
3 | 102000022222101122211101022 |
4 | 231100212202320310022 |
5 | 401424143432031442 |
6 | 10340450232152442 |
7 | 440463505214336 |
oct | 55204642706412 |
9 | 12008871584338 |
10 | 3110203002122 |
11 | a9a03656a337 |
12 | 422940838722 |
13 | 1973a20c56b8 |
14 | aa76b0407c6 |
15 | 55d8458a3d2 |
hex | 2d4268b8d0a |
3110203002122 has 4 divisors (see below), whose sum is σ = 4665304503186. Its totient is φ = 1555101501060.
The previous prime is 3110203002113. The next prime is 3110203002217. The reversal of 3110203002122 is 2212003020113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1604303425321 + 1505899576801 = 1266611^2 + 1227151^2 .
It is a super-3 number, since 3×31102030021223 (a number of 38 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 3110203002122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777550750529 + ... + 777550750532.
Almost surely, 23110203002122 is an apocalyptic number.
3110203002122 is a deficient number, since it is larger than the sum of its proper divisors (1555101501064).
3110203002122 is a wasteful number, since it uses less digits than its factorization.
3110203002122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1555101501063.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 3110203002122 its reverse (2212003020113), we get a palindrome (5322206022235).
The spelling of 3110203002122 in words is "three trillion, one hundred ten billion, two hundred three million, two thousand, one hundred twenty-two".
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