Base | Representation |
---|---|
bin | 100011010110111110011100… |
… | …0010010000100010001000000 |
3 | 1111210020022120022200121021100 |
4 | 1012231330320102010101000 |
5 | 311231232002224000000 |
6 | 3021253024140054400 |
7 | 122340345226344564 |
oct | 10655747022042100 |
9 | 1453208508617240 |
10 | 311021001000000 |
11 | 901122a1844585 |
12 | 2aa71b53b34400 |
13 | 10471201700b95 |
14 | 56b36d51c16a4 |
15 | 25e5583ab1a00 |
hex | 11adf38484440 |
311021001000000 has 1176 divisors, whose sum is σ = 1211803268563368. Its totient is φ = 75949056000000.
The previous prime is 311021000999987. The next prime is 311021001000007. The reversal of 311021001000000 is 100120113.
It can be written as a sum of positive squares in 28 ways, for example, as 289625121677376 + 21395879322624 = 17018376^2 + 4625568^2 .
It is a Harshad number since it is a multiple of its sum of digits (9).
It is not an unprimeable number, because it can be changed into a prime (311021001000007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 5660972530 + ... + 5661027470.
Almost surely, 2311021001000000 is an apocalyptic number.
311021001000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 311021001000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (605901634281684).
311021001000000 is an abundant number, since it is smaller than the sum of its proper divisors (900782267563368).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311021001000000 is an equidigital number, since it uses as much as digits as its factorization.
311021001000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55043 (or 55005 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 311021001000000 its reverse (100120113), we get a palindrome (311021101120113).
The spelling of 311021001000000 in words is "three hundred eleven trillion, twenty-one billion, one million", and thus it is an aban number.
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