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311022220114 = 2155511110057
BaseRepresentation
bin1001000011010100101…
…11100111001101010010
31002201210200011211020201
410201222113213031102
520043433142020424
6354514233325414
731320264152014
oct4415227471522
91081720154221
10311022220114
1110a9a3a31421
125034086686a
1323438536048
14110a6d581b4
15815518bd44
hex486a5e7352

311022220114 has 4 divisors (see below), whose sum is σ = 466533330174. Its totient is φ = 155511110056.

The previous prime is 311022220049. The next prime is 311022220183. The reversal of 311022220114 is 411022220113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 215737025625 + 95285194489 = 464475^2 + 308683^2 .

It is a junction number, because it is equal to n+sod(n) for n = 311022220091 and 311022220100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77755555027 + ... + 77755555030.

Almost surely, 2311022220114 is an apocalyptic number.

311022220114 is a deficient number, since it is larger than the sum of its proper divisors (155511110060).

311022220114 is a wasteful number, since it uses less digits than its factorization.

311022220114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155511110059.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 311022220114 its reverse (411022220113), we get a palindrome (722044440227).

Subtracting 311022220114 from its reverse (411022220113), we obtain a palindrome (99999999999).

The spelling of 311022220114 in words is "three hundred eleven billion, twenty-two million, two hundred twenty thousand, one hundred fourteen".

Divisors: 1 2 155511110057 311022220114