Base | Representation |
---|---|
bin | 1110001001001100110001… |
… | …10001111101011111101111 |
3 | 11002010100210020002121122100 |
4 | 13010212120301331133233 |
5 | 13034040224341032421 |
6 | 150052131040150143 |
7 | 6360034666030242 |
oct | 704463061753757 |
9 | 132110706077570 |
10 | 31102421424111 |
11 | 9a015100678a4 |
12 | 35a3a36008353 |
13 | 1447c3aa9484b |
14 | 79751828d259 |
15 | 38e0a3133c26 |
hex | 1c4998c7d7ef |
31102421424111 has 12 divisors (see below), whose sum is σ = 45662207046040. Its totient is φ = 20395030441680.
The previous prime is 31102421424079. The next prime is 31102421424197. The reversal of 31102421424111 is 11142412420113.
31102421424111 is a `hidden beast` number, since 3 + 1 + 1 + 0 + 242 + 1 + 4 + 2 + 411 + 1 = 666.
It is not a de Polignac number, because 31102421424111 - 25 = 31102421424079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31102421425111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28326430621 + ... + 28326431718.
Almost surely, 231102421424111 is an apocalyptic number.
31102421424111 is a deficient number, since it is larger than the sum of its proper divisors (14559785621929).
31102421424111 is a wasteful number, since it uses less digits than its factorization.
31102421424111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56652862406 (or 56652862403 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 31102421424111 its reverse (11142412420113), we get a palindrome (42244833844224).
The spelling of 31102421424111 in words is "thirty-one trillion, one hundred two billion, four hundred twenty-one million, four hundred twenty-four thousand, one hundred eleven".
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