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31103102013 = 310367700671
BaseRepresentation
bin11100111101111000…
…111010110000111101
32222021121222021212020
4130331320322300331
51002144343231023
622142155230353
72150523001464
oct347570726075
988247867766
1031103102013
1112210987995
1260404483b9
132c18a90999
141710b539db
15c208c3de3
hex73de3ac3d

31103102013 has 4 divisors (see below), whose sum is σ = 41470802688. Its totient is φ = 20735401340.

The previous prime is 31103101943. The next prime is 31103102021. The reversal of 31103102013 is 31020130113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31103102013 - 29 = 31103101501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31103101983 and 31103102001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31103102213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5183850333 + ... + 5183850338.

It is an arithmetic number, because the mean of its divisors is an integer number (10367700672).

Almost surely, 231103102013 is an apocalyptic number.

It is an amenable number.

31103102013 is a deficient number, since it is larger than the sum of its proper divisors (10367700675).

31103102013 is a wasteful number, since it uses less digits than its factorization.

31103102013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10367700674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 31103102013 its reverse (31020130113), we get a palindrome (62123232126).

The spelling of 31103102013 in words is "thirty-one billion, one hundred three million, one hundred two thousand, thirteen".

Divisors: 1 3 10367700671 31103102013