Base | Representation |
---|---|
bin | 1110001001001110000100… |
… | …00000100111100001100011 |
3 | 11002010102120102200000122220 |
4 | 13010213002000213201203 |
5 | 13034043133430212011 |
6 | 150052323430002123 |
7 | 6360061065324555 |
oct | 704470200474143 |
9 | 132112512600586 |
10 | 31103113132131 |
11 | 9a01835563317 |
12 | 35a3ba97a6343 |
13 | 144801b18c931 |
14 | 7975820a94d5 |
15 | 38e0e3c19506 |
hex | 1c49c2027863 |
31103113132131 has 8 divisors (see below), whose sum is σ = 41749145144400. Its totient is φ = 20596244937312.
The previous prime is 31103113132103. The next prime is 31103113132153. The reversal of 31103113132131 is 13123131130113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31103113132131 - 26 = 31103113132067 is a prime.
It is a super-2 number, since 2×311031131321312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31103113132031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34790953840 + ... + 34790954733.
It is an arithmetic number, because the mean of its divisors is an integer number (5218643143050).
Almost surely, 231103113132131 is an apocalyptic number.
31103113132131 is a deficient number, since it is larger than the sum of its proper divisors (10646032012269).
31103113132131 is a wasteful number, since it uses less digits than its factorization.
31103113132131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69581908725.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 31103113132131 its reverse (13123131130113), we get a palindrome (44226244262244).
The spelling of 31103113132131 in words is "thirty-one trillion, one hundred three billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred thirty-one".
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