3110331323113 has 4 divisors (see below), whose sum is σ = 3554664369280. Its totient is φ = 2665998276948.

The previous prime is 3110331323107. The next prime is 3110331323147. The reversal of 3110331323113 is 3113231330113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3110331323113 - 2⁵ = 3110331323081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3110331323213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222166523073 + ... + 222166523086.

It is an arithmetic number, because the mean of its divisors is an integer number (888666092320).

Almost surely, 2^{3110331323113} is an apocalyptic number.

It is an amenable number.

3110331323113 is a deficient number, since it is larger than the sum of its proper divisors (444333046167).

3110331323113 is an equidigital number, since it uses as much as digits as its factorization.

3110331323113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444333046166.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 3110331323113 its reverse (3113231330113), we get a palindrome (6223562653226).

The spelling of 3110331323113 in words is "three trillion, one hundred ten billion, three hundred thirty-one million, three hundred twenty-three thousand, one hundred thirteen".