31104044040113 has 8 divisors (see below), whose sum is σ = 33932393323776. Its totient is φ = 28275812909200.

The previous prime is 31104044040109. The next prime is 31104044040133.

It is a happy number.

31104044040113 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31104044040113 - 2² = 31104044040109 is a prime.

It is a super-3 number, since 3×31104044040113³ (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31104044040133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28987298 + ... + 30041163.

It is an arithmetic number, because the mean of its divisors is an integer number (4241549165472).

Almost surely, 2^{31104044040113} is an apocalyptic number.

It is an amenable number.

31104044040113 is a deficient number, since it is larger than the sum of its proper divisors (2828349283663).

31104044040113 is a wasteful number, since it uses less digits than its factorization.

31104044040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59076375.

The product of its (nonzero) digits is 2304, while the sum is 26.

It can be divided in two parts, 3110404 and 4040113, that added together give a palindrome (7150517).

The spelling of 31104044040113 in words is "thirty-one trillion, one hundred four billion, forty-four million, forty thousand, one hundred thirteen".