Base | Representation |
---|---|
bin | 101101010001010110000… |
… | …100011111101110110111 |
3 | 102000102000221222212021211 |
4 | 231101112010133232313 |
5 | 401432312041411211 |
6 | 10341101314022251 |
7 | 440522326406623 |
oct | 55212604375667 |
9 | 12012027885254 |
10 | 3111000341431 |
11 | a9a405653144 |
12 | 422b23877987 |
13 | 19749b3564c8 |
14 | aa804cb6183 |
15 | 55dce588e21 |
hex | 2d45611fbb7 |
3111000341431 has 4 divisors (see below), whose sum is σ = 3111202593072. Its totient is φ = 3110798089792.
The previous prime is 3111000341429. The next prime is 3111000341437. The reversal of 3111000341431 is 1341430001113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3111000341431 - 21 = 3111000341429 is a prime.
It is a super-3 number, since 3×31110003414313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111000341437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101102746 + ... + 101133511.
It is an arithmetic number, because the mean of its divisors is an integer number (777800648268).
Almost surely, 23111000341431 is an apocalyptic number.
3111000341431 is a deficient number, since it is larger than the sum of its proper divisors (202251641).
3111000341431 is a wasteful number, since it uses less digits than its factorization.
3111000341431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202251640.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3111000341431 its reverse (1341430001113), we get a palindrome (4452430342544).
The spelling of 3111000341431 in words is "three trillion, one hundred eleven billion, three hundred forty-one thousand, four hundred thirty-one".
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